Physics, asked by Akanksha111, 1 year ago

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Attachments:

QGP: That is, the acceleration depends upon both initial and final velocity during the given time period
QGP: Here's an example:
QGP: Suppose you throw a ball vertically upwards. As it goes upwards, it's velocity decreases and finally becomes zero at maximum height. Here, it's velocity is zero, but a constant gravitational acceleration g is still acting on it
QGP: Thus, a body having zero velocity will not necessarily have zero acceleration
QGP: Hope it helps. -Purva, @Purvaparmar1405, Brainly.in
Akanksha111: why didnt u answered??? I would have marked u brainliest
QGP: At that time, two (wrong) answers were already there. So, I reported them, and wrote them here in the comments
Akanksha111: oohhkkk
Akanksha111: thank u
QGP: Welcome

Answers

Answered by QGP
1
Hello Friend,

The correct answer is option (A). Here's how:

Acceleration is defined as the change in velocity per unit time.

So, a = (v-u)/t

Here, you can directly see that even if velocity v = 0, then we cannot say that acceleration is zero.
As here, a = (0-u)/t = -u/t

That is, the acceleration depends upon both initial and final velocity during the given time period

Here's an example:

Suppose you throw a ball vertically upwards. As it goes upwards, it's velocity decreases and finally becomes zero at maximum height. Here, it's velocity is zero, but a constant gravitational acceleration g is still acting on it

Thus, a body having zero velocity will not necessarily have zero acceleration

Hope it helps.

Purva
@Purvaparmar1405
Brainly.in
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