Question

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Answer 1

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Answer 2

Question:

• A cricket ball of mass 0.5 kg is moving with a velocity of 100 m/s. The wavelength associated with it's motion is
• $(1)\frac{1}{100 }\;cm$
• $(2)66 \times {10}^{-34} \:m$
• $(3)1.32 \times {10}^{-35} \;m$
• $(4)6.6 \times {10}^{-28}\: m$

Answer:

• $\large\bold\red{(3)1.32\times{10}^{-35}\:m}$

Explanation:

Given,

A cricket ball.

• Mass , m = 0.5 Kg
• Velocity, v = 100 m/s

Now,

We have to find it's wavelength.$\bold{(\lambda)}$

But,

We know that,

• $\boxed{\large \bold \green{\lambda = \frac{h}{mv}} }$

Where,

• h = Planks Constant
• $\bold{Value\:of\:h=6.63\times{10}^{-34}\:J-s}$

So,

Putting the values,

We get,

$= > \lambda = \frac{6.63 \times {10}^{ - 34} }{0.5 \times 100} \\ \\ = > \lambda = \frac{6.63 \times {10}^{ - 34} }{5 \times {10}^{1 } } \\ \\ = > \lambda = \cancel\frac{6.63}{5} \times {10}^{ (- 34 - 1)} \\ \\ = > \lambda = 1.32 \times {10}^{ - 35}$

Hence,

The correct Answer is,

$\large\bold{(3)1.32\times{10}^{-35}\:m}$