Question

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Answer 1

$\huge\underline{\underline{\mathfrak \red{A}\green{n}\orange{s}\pink{W}\blue{e}\red{r}}}$

Option (3)

Answer 2

Question:

• An electron in hydrogen atom jumps from third energy level to first energy level.The change in potential energy of the electron is
• (1)12.09 eV
• (2)6.04 eV
• (3)24.18 eV
• (4)3.01 eV

Answer:

$\large\bold\red{(3)24.18\;eV}$

Explanation:

Given,

An electron in hydrogen atom jumps from third to first energy level.

But,

We know that,

$\large\boxed{ \bold \pink{\triangle E = 13.6 {z}^{2} ( \frac{1}{ {n_{1}}^{2} } - \frac{1}{ {n_{2}}^{2} } )eV}}$

Here,

We have,

• $\bold{z = 1}$
• $\bold{n_{1}=1}$
• $\bold{n_{2}=3}$

So,

Putting the values,

We get,

$= > \triangle E = 13.6 \times 1( \frac{1}{ {1}^{2} } - \frac{1}{ {3}^{2} } ) \\ \\ = > \triangle E = 13.6(1 - \frac{1}{9} ) \\ \\ = > \triangle E = 13.6( \frac{9 - 1}{9} ) \\ \\ = > \triangle E = 13.6 \times \frac{8}{9}$

Now,

Lets take Potential Energy as P.E

But,

We know that,

$\large\boxed{ \bold{P.E = 2\triangle E }}$

Therefore,

We get,

$= > P.E = 2 \times 13.6 \times \frac{8}{9} \\ \\ = > P.E = 16 \times \cancel\frac{13.6}{9} \\ \\ = >P.E = 16 \times 1.5 011\\ \\ = > P.E = 24.18$

Hence,

The correct answer is,

$\large\bold{(3)24.18\;eV}$