Question

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Answer 1

Answer:

$(\sqrt[3]{64} )^{ - 2} \\ = {64}^{ \frac{1}{3} \times - 2 } \\ = {64}^{ \frac{ - 2}{3 } } \\ = {2}^{6 \times \frac{ - 2}{3} } \\ = {2}^{ - 4} \\ = \frac{1}{ {2}^{4} } \\ = \frac{1}{16}$

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