Math, asked by lucifer2619, 10 months ago

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Answered by Siddharta7
2

Answer:

x = (2ab - bc - ac)/(a + b - 2c)

Step-by-step explanation:

(a/x - a) + (b/x - b) = (2c/x - c)

=> a(x - b)(x - c) + b(x - a)(x - c) = 2c(x - a)(x - b)

=> a(x² - cx - bx + bc) + b(x² - cx - ax + ac) = 2c(x² - ax - bx + ab)

=> ax² - acx - abx + abc + bx² - bcx - bax + bac = 2x²c - 2xac - 2cbx + 2cab

=> ax² + bx² - 2cx² - 2abx + bcx + acx = 0

=> x(ax + bx - 2cx - 2ab + bc + ac) = 0

=> ax + bx - 2cx - 2ab + bc + ac = 0

=> x(a + b - 2c) = 2ab - bc - ac

=> x = (2ab - bc - ac)/(a + b - 2c)

Hope it helps!

Answered by EliteSoul
3

Answer:

Heya mate!!!!!Here is ur answer in the attachment ❤❤❤

Hope it helps you ❤❤❤

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