Question

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Answer 1

h(x) = ax + b

h(3) = 26

3a + b = 26

multiply by 47

141a + 47b = 1222      -------------eq1

g(x) = 2x + 5

$g^{-1}$(21) = h(1)

1 / (2 x 21 + 5) = 1 x a + b

1 / 47 = a + b

47a + 47b = 1       ---------------eq2

Subtracting eq2 from eq1

94a = 1221

a = 1221/94

Put in eq2

47 x 1221/94 + 47b = 1

47b = 1 - 1221/2

47b = (2 - 1221) / 2

b = -1219 / 94

Therefore,

a = 1221 / 94 , b = -1219 / 94 : Ans

Hope I helped