Physics, asked by deep558739, 8 months ago

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Answered by Abhishek474241
3

AnSwEr

{\tt{\red{\underline{\large{Given}}}}}

  • A piston of cross section area =100cm²
  • Exert a force of =10⁷dyne
  • Having Other piston supports having mass of 2000kg

{\sf{\green{\underline{\large{To\:find}}}}}

  • Cross section area of other piston

{\sf{\pink{\underline{\Large{Explanation}}}}}

we know that

\boxed{\boxed{\sf\red{Pressure=\dfrac{Force}{Area}}}}

Changing the units

Piston 1

  • Area =100cm²a=0.01M²

  • Force=10⁷dyne=10³N

Here pressure

\boxed{\boxed{\sf\red{Pressure=\dfrac{Force}{Area}}}}

\implies\tt\dfrac{100}{0.01}

\implies\tt{100\times{100}}

=>10000

Piston 2

  • From Pascal law The pressure on fluids are eual

Therefore

  • Piston1=Piston2=Pressure

Force = m×a(gravity)

=>f=2000kg×10m/s²

=>20000N

Now

\boxed{\boxed{\sf\red{Pressure=\dfrac{Force}{Area}}}}

Putting values

\implies\tt{10000}=\dfrac{20000}{Area}

Area=2m²

changing into cm²

=>2×100×100

=>2×10⁴

Answered by Anonymous
41

  \large{\red{ \bf{ \underline {\underline{Answer}}}}} \\  \\  \purple{ \sf{\mapsto 2 \times  {10}^{4} \:  {cm}^{2}  }} \\  \\   \mathbf{\green{ \underline{Given}}} \\  \\  \sf{ \rightsquigarrow Piston \: of \: cross \: section \: area  =  100 \:  {m}^{2} } \\  \\ \sf{ \rightsquigarrow Exert \: a \: force  =  {10}^{7} } \\  \\ \sf{ \rightsquigarrow Other \: piston \: supports \: having \: mass = 200 \: Kg}\\ \\ \mathbf {\blue{ \underline{ To \: Find}}} \\  \\  \sf{ \rightsquigarrow Cross \: section \: area \: of \: other \: position\:=\:?}

⠀⠀

According To Given Question

⠀⠀

\text {\sf{By Pascal's law of transmission of fluid pressure.}} \\    \text{\sf{The pressure from piston 1 is equally transmitted}} \\  \sf{ to  \: piston  \: 2.}  \\  \\  \sf{ \implies P_1=P_2}\\ \\ \sf{ \implies \frac{F_1}{A_1}= \frac{F_2}{P_2}}\\ \\ \sf{ \implies F_1 =  {10}^{7}  \: dyne} \\  \\  \sf{ \implies F_1=  {10}^{2} \: N } \\  \\  \sf{ \implies A_1 =  \:  100 \: {cm}^{2} =  \frac{100}{1000 } } \\  \\  \sf{ \implies A_1 =  {10}^{ - 2} \:  {m}^{2}   } \\  \\  \sf{ \implies F_2  = Mg = 2000 \: Kg \times 10 \: m/s} \\  \\  \sf{ \implies F_2 = 20000 \: N} \\  \\ \sf{ \implies A_2 =  \: ?} \\  \\  \sf{ \implies \frac{ {10}^{2} }{ {10}^{ - 2} } } =  \frac{20000}{A_2}  \\  \\  \sf{ \implies {10}^{4}  \: A_2 = 20000} \\  \\  \sf{ \implies A_2 =  \frac{2 \cancel{0000}}{1 \cancel{0000} }} \\  \\  \sf{ \implies A_2 =  2 \:  {m}^{2} } \\  \\  \sf{ A_2 \: must \: be \: 2 \:  {m}^{2} } \\  \\  \sf{ \purple{ \implies}} \purple{ \underline{ \boxed{ \sf{2 \times  {10}^{4}  \:  {cm}^{2} }}}} \\  \\  \rm{\therefore\:\:Option\:(C)\:is \:right\:\checkmark}

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