Question

___________________??

Answer 1

SOLUTION ::

Zn(s) → Zn^(2+) (aq) + 2e- ; EΦ = 0.76 V

Ag2O(s) + H2O(l) +2e- → 2Ag(s) + 2OH−(aq) ; EΦ =0.344V

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Addition Genetates

Zn(s) + Ag2O(s) + H2O(l) → Zn2+(aq) + 2Ag(s) + 2OH−(aq) ; EΦ =1. 104V

Hence EΦ =1. 104V

Here n=2

We know that

ΔrGΦ = - n FEΦ

= - 2 × 96487 × 1.104

= - 213403.296 J

= - 213.04 KJ

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Answer 2

Answer:

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