Math, asked by Anonymous, 8 months ago

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Answered by jeniffer04
2

Answer:

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2 −4xy+8y 2 +2x−4y−8=0 are at right angles of each other.

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ANSWER

3x−y−2=0 or

2

3x−y

=1.

Making the equation of the curve homogenous, we get

7x 2 −4xy+8y 2+(2(x−2y) 2(3x−y) −8⋅( 23x−y ) 2=0(7x 2 −4xy+8y

2m )+(3x − 7xy+2y 2 )−2(9x 2−6xy+y 2 )=0or −8x 2 +xy+8y 2

=0 is the required equation to the lines.

Since a+b=−8+8=0, and hence the lines are perpendicular.

please mark as brainliest

Answered by khushi02022010
8

Answer:

2 −4xy+8y 2 +2x−4y−8=0 are at right angles of each other.

Share

Study later

ANSWER

3x−y−2=0 or

2

3x−y

=1.

Making the equation of the curve homogenous, we get

7x 2 −4xy+8y 2+(2(x−2y) 2(3x−y) −8⋅( 23x−y ) 2=0(7x 2 −4xy+8y

2m )+(3x − 7xy+2y 2 )−2(9x 2−6xy+y 2 )=0or −8x 2 +xy+8y 2

=0 is the required equation to the lines.

Since a+b=−8+8=0, and hence the lines are perpendicular.

please mark as brainliest

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