Question

___________________??

Answer 1

◘ Given ◘

The resultant of two forces one double the other in magnitudes is perpendicular to the smaller of the two forces.

◘ To Find ◘

The angle between the forces.

◘ Solution ◘

Let the two forces be F₁ and F₂ .

Now,

► |F₁| = 2 × |F₂|         (Given)

From the above relation, we get that the force F₂ is smaller.

According to the given conditions,

R is perpendicular to F₂.

We know,

• R = Sum of the 2 forces

→ R = F₁ + F₂

Finally, we get :-

R × F₂ = 0         (As it is perpendicular)

→ (F₁ + F₂) × F₂ = 0

→ F₁ . F₂ + F₂² = 0

Taking magnitude :

→ ( |F₁| . |F₂| cosθ ) + |F₂|² = 0

→ ( 2 × |F₂| . |F₂| cosθ ) + |F₂|² = 0

→ 2 |F₂|² cosθ + |F₂|² = 0

Taking |F₂|² common :-

→ |F₂|² (2 cosθ + 1) = 0

→ 2 cosθ + 1 = 0

→ 2 cosθ = -1

→ cosθ = -1/2

→ cosθ = cos 120°

→ θ = 120°

Therefore, the angle between the forces is 120°.

Answer 2

Answer:

vote

answered Jul 20, 2017 by Shivansh Basic (26 points)

Take F1=x and F2= 2x acc to question

Now as R makes 90° with F1 .. apply pythogorous tum

R sq = x sq + 2x sq

Rsq = 9x sq

R= 3x

Rsq =√a sq + b sq + 2 ab cos©

3x sq = 6 x cos©

Cos© = -1\2

© = 120°

Guys it took so much to type please thank it will be good

Explanation:

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