Math, asked by legenesisindia, 8 months ago

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Answered by RajvanshiC

0

Step-by-step explanation:

Your answer is attached...

..feel free to ask any doubt

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Answered by Anonymous

1

Step-by-step explanation:

we have LHS

sin²A/cos²+cos²/sin²

(sin²A×sin²A+cos²A+cos²A)/sin²A.cos²A

(sin²A)²+(cos²A)²/sin²A.cos²A

(1-cos²A)²+cos⁴A/sin²A.cos²A

1+cos⁴A-2cos²A+cos⁴A/sin²A.cos²A

sin⁴A+cos⁴A-2cos²/sin²A.cos²A

1-2cos²/sin²A.cos²A

1 / sin²A.cos²A-2cos²A/sin²A.cos²A

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