Question

____________________??

Answer 1

Answer:

option (b) π/3

Step-by-step explanation:

$a \: = \binom{cos \alpha \: \: - sin \alpha }{sine \alpha \: \: \: \: cos \alpha } \\ a 1 \: = \binom{cos \alpha \: \: \: sin \alpha }{ - sine \alpha \: \: \: \: cos \alpha } \\ \\ now. \\ a + a1 = i \\ \\ \binom{2 \cos( \alpha ) \: \: \: \: 0 }{0 \: \: \: \: 2 \cos( \alpha ) } = \binom{1 \: \: \: 0}{0 \: \: \: 1} \\ </p><p> comparing the corresponding</p><p> element of two matrix </p><p> ,we have</p><p>2 \cos( \alpha ) = 1 \\ \\ \cos( \alpha ) = \frac{1}{2} \\ \\ \cos( \frac{\pi}{2} ) \\ \\ \\ therefore \: \: \: \alpha = \frac{\pi}{3}$

Answer 2

Step-by-step explanation:

Answer:

option (b) π/3

Step-by-step explanation:

$$\begin{lgathered}a \: = \binom{cos \alpha \: \: - sin \alpha }{sine \alpha \: \: \: \: cos \alpha } \\ a 1 \: = \binom{cos \alpha \: \: \: sin \alpha }{ - sine \alpha \: \: \: \: cos \alpha } \\ \\ now. \\ a + a1 = i \\ \\ \binom{2 \cos( \alpha ) \: \: \: \: 0 }{0 \: \: \: \: 2 \cos( \alpha ) } = \binom{1 \: \: \: 0}{0 \: \: \: 1} \\ comparing the corresponding element of two matrix ,we have 2 \cos( \alpha ) = 1 \\ \\ \cos( \alpha ) = \frac{1}{2} \\ \\ \cos( \frac{\pi}{2} ) \\ \\ \\ therefore \: \: \: \alpha = \frac{\pi}{3}\end{lgathered}$$