Math, asked by Anonymous, 8 months ago

_____________________??​

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Answered by Anonymous
16

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∫e^x(tanx+1)secx

=∫e^x(secx.tanx + secx)

it is of form

∫e^x(f(x) + f'(x))

=e^x.f(x) + C

here, f(x) = secx

hence,

I = e^x.f(x) + C

= e^xsecx + C

Answered by aloksingh17801980
0

Answer:

∫e^x(tanx+1)secx

=∫e^x(secx.tanx + secx)

it is of form

∫e^x(f(x) + f'(x))

=e^x.f(x) + C

here, f(x) = secx

hence,

I = e^x.f(x) + C

= e^xsecx + C

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