Question

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Answer 1

$\huge\underline\bold\red{ƛƝƧƜЄƦ}$

Use integration by substitution.

Let 1 + x = u. In that case, du = dx.

Thus, int [1/(1+x)^2] dx = int [1/u^2] du

= int [u^-2] du

= -u^-1 + C

= -1/u + C

= -1/(1+x) + C

where C = any arbitrary constant.

I hope that helps! :)

Answer 2

Answer:

$\huge\mathbb\red{Hello\:Mates}$

Use integration by substitution.

Let 1 + x = u. In that case, du = dx.

Thus, int [1/(1+x)^2] dx = int [1/u^2] du

= int [u^-2] du

= -u^-1 + C

= -1/u + C

= -1/(1+x) + C

where C = any arbitrary constant.

I hope that helps! :)