Question

Writeabalancedchemicalequationforthefollowingchemicalreaction.

“Aqueoussolutionofcommonsaltreactswithcarbondioxideandammoniato



fromammoniumchlorideandsodiumhydrogencarbonate.”​

Answer 1

Answer:

Explanation:

Correct Question:-

Write a balanced chemical equation for the following chemical reaction.

“Aqueous solution of common salt reacts with carbon dioxide and ammonia to  from ammonium chloride and sodium hydrogen carbonate.”​

ANSWER:-

• Common salt is Sodium Chloride
• We need to show that Sodium Chloride+Carbon Dioxide + Ammonia gives us Sodium Hydrogen Carbonate.

$\sf{NaCl + CO_2 + H_2O+NH_3 \longrightarrow NH_4Cl+ NaHCO_3}$

1. Sodium is 1 in both sides, hence balanced.
2. Chlorine is 1 in both sides hence balanced.
3. Carbon is 1 in both side hence balanced.
4. Oxygen is 2 in CO2 and 1 in H2O hence 3 in both sides.
5. Hydrogen is 3 in NH3 and 2 in H2O hence 5 and balanced in both sides.
6. Nitrogen is 1 in both sides hence balanced.

• Overall equation is balanced.

Note:-

• Always when aqueous is written it means water is added in it.
• Maintain the equation by checking whether it is balanced or not.

Answer 2

Answer:

Explanation:

Correct Question:-

Write a balanced chemical equation for the following chemical reaction.

“Aqueous solution of common salt reacts with carbon dioxide and ammonia to  from ammonium chloride and sodium hydrogen carbonate.”

ANSWER:-

Common salt is Sodium Chloride

We need to show that Sodium Chloride+Carbon Dioxide + Ammonia gives us Sodium Hydrogen Carbonate.

$\sf{NaCl + CO_2 + H_2O+NH_3 \longrightarrow NH_4Cl+ NaHCO_3}$

Sodium is 1 in both sides, hence balanced.

Chlorine is 1 in both sides hence balanced.

Carbon is 1 in both side hence balanced.

Oxygen is 2 in CO2 and 1 in H2O hence 3 in both sides.

Hydrogen is 3 in NH3 and 2 in H2O hence 5 and balanced in both sides.

Nitrogen is 1 in both sides hence balanced.

Overall equation is balanced.

Note:-

Always when aqueous is written it means water is added in it.

Maintain the equation by checking whether it is balanced or not.