Question

একটি উপক্ষার এর নাম​

Answer 1

Answer:

Given PA & PB are tangent to the circle with center O.

PA=PB [length of tangent from external point to circle are equal]

In ΔPAB

PA=PB

∠PBA=∠PAB [isosceles triangle]

now ∠PAB+∠PBA+∠APB=180o [Angle sum prop]

2∠PAB=180−50=130

∠PBA=∠PAB=65o ………..(1)

Now PA is tangent & OA is radius at point A.

∠OAP=90o [tangent at any point is ⊥ to radius]

∠OAB=∠OAP−∠PAB=90−65=25o

Hence angle OAB is 25o.

Explanation: