Question

???????????????????????

Answer 1

7.1 6/36 =1/6. (1,1)(2,2)(3,3)(4,4)(5,5)(6,6)
7.2 3/36 = 1/12. (4,6)(5,5)(6,4)

Answer 2

Hey there!
Down here⏬

> If x=3 is one root of the quadratic equation

$p(x) = x {}^{2} - 2kx - 6 = 0$

Find the value of k


$p(3) = (3) {}^{2} - 2 \times k \times 3 - 6 = 0$

$9 - 6k - 6 = 0$

$3 - 6k = 0$

$6k = 0 + 3$

$k = \frac{3}{6}$

$k = \frac{1}{2}$

Hope helped.