Question

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∆ᴀʙᴄ ɪꜱ ʀɪɢʜᴛ ᴀɴɢʟᴇᴅ ᴀᴛ ᴀ.
ʟ ɪꜱ ᴀ ᴘᴏɪɴᴛ ᴏɴ ʙᴄ ꜱᴜᴄʜ ᴛʜᴀᴛ ᴀʟ ɪꜱ ᴛʜᴇ ᴘᴇʀᴘᴇɴᴅɪᴄᴜʟᴀʀ ʙɪꜱᴇᴄᴛᴏʀ ᴏꜰ ʙᴄ. ᴘʀᴏᴠᴇ ᴛʜᴀᴛ ᴀɴɢʟᴇ ʙᴀʟ = ᴀɴɢʟᴇ ᴀᴄʙ
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Answer 1

Answer:

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Answer 2

Answer:

In △ABL,

∠BAL+∠ALB+∠B=180°

∠BAL+90°+∠B=180°

∠BAL=90°−∠B -----(1)

ㅤ

In △ABC,

∠A+∠B+∠C=180°

∠B+∠C=90°

∠C=90°−∠B

∠ACB=90° −∠B -----(2)

$From\;1\;and\;2,\;we\;get,$

$\large\underline\bold{∠BAL=∠ACB}$

$\underline{Thus\;Proved.}$

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$Hope\;this\;Helps:)$

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