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c) sin (40+x)cos (10+x)-cos(40+x)sin(10+x)=1/2
we know
sinAcosB-cosAsinB=sin(A-B)
then, the upper equation is
sin(40+x-10-x)
=sin 30
=1/2(proved)
b)sin x=12/13
cos 2x
=cos^2x-sin^2x
=1-sin^2x-sin^2x
=1-2sin^2x
=1-2.(12/13)^2
=1-2.144/169
=1-288/169
=(169-288)/169
= -119/169
a)20°40'into radian
we know,
180°=π radian
20°40'=20°40/60°=20 2/3°=62/3°
62/3°=π×62/3×180°=62π/540°
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ali moti sanai
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