India Languages, asked by Anonymous, 2 months ago

કોઈ ઓનલાઈન છે મારા ફોલોવિંગ માંથી???​

Answers

Answered by Anonymous
1

ઓય નંદિની યાર ઓનલાઇન તો આવ યાર અમારા સાથે થોડી બ્રેક અપ કરી લીધું છે તે અમારી જોડે તો કર વાત

Answered by Ranveerx107
2

Additional Information :-

\sf Trigonometric\: Table \\ \begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\boxed{\begin{array}{ |c |c|c|c|c|c|} \bf\angle A & \bf{0}^{ \circ} & \bf{30}^{ \circ} & \bf{45}^{ \circ} & \bf{60}^{ \circ} & \bf{90}^{ \circ} \\ \\ \rm sin A & 0 & \dfrac{1}{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{ \sqrt{3}}{2} &1 \\ \\ \rm cos \: A & 1 & \dfrac{ \sqrt{3} }{2}& \dfrac{1}{ \sqrt{2} } & \dfrac{1}{2} &0 \\ \\ \rm tan A & 0 & \dfrac{1}{ \sqrt{3} }&1 & \sqrt{3} & \rm  \infty  \\ \\ \rm cosec A & \rm  \infty  & 2& \sqrt{2} & \dfrac{2}{ \sqrt{3} } &1 \\ \\ \rm sec A & 1 & \dfrac{2}{ \sqrt{3} }& \sqrt{2} & 2 & \rm  \infty  \\ \\ \rm cot A & \rm  \infty  & \sqrt{3} & 1 & \dfrac{1}{ \sqrt{3} } & 0 \end{array}}}\end{gathered}\end{gathered}\end{gathered} \end{gathered}

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