Question

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Answer 1

Answer:

$i. \: total \: molecular \: mass \: of \: nh4no3 \: = \: 14 + (1 \times 4) + 14 + (16 \times 3) = 80u$

$in \: that \: n \: is \: 28u$

$so \: the \: percentage \: = 35\%$

$ii. \: relative \: mass \: of \: ch3coona \: = \: 12 + (1 \times 3) + 12 + 16 + 16 + 23 = 82u$

$iii. \: the \: total \: molecular \: mass \: of \: mgso4.7h2o \: = \: 24 + 32 + (16 \times 4) + 7 \times (2 + 16) = 246u$

$in \: that \: water \: is \: 126u$

$so \: the \: percentage \: = \: 51.21\%$

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