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Answered by IIDakshII
2

ᴀɴsᴡᴇʀ →

HCl is a strong acid. All acids have a pH in the acid range, that is to say below 7.

The concentration of HCl = 10−8 M

Total [H+] = [H+] obtained from HCL +[H+] obtained from H2O

HCl being strong acid, it completely ionizes.

[H+] HCl = 1.0 x 10-8.

The concentration of H+ from ionization is equal to the [OH–] from water and let us consider it is equal to x.

[H+] H2O = [OH–] H2O = x

Total [H+] = x + 1.0 x 10-8………………………(1)

But we know

[H+] [OH–] = 1.0 x 10-14

(1.0 x 10-8 + x) (x) = 1.0 x 10-14

X2 + 10-8 x – 10-14 = 0

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Solving x we get

x = 9.5 x 10-8

Substituting x value in equation (1)

Total [H+] = 9.5 x 10-8 + 1.0 x 10-8

Total [H+] = 1.05 x 10-7.

Consider an equation

pH = – log [H+]

pH = – log [1.05 x 10-7]

pH = 6.98

Answered by aadyasahxoxo
1

Step-by-step explanation:

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