⠀⠀⠀. ⠀⠀⠀✦ ⠀ ⠀ ⠀⠀⠀⠀⠀* ⠀⠀⠀. . ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀✦⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀☄️ ⠀ ⠀⠀⠀⠀⠀⠀. . ﾟ . . ✦ , . ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀☀️ * . . ✦⠀ , * ⠀ ⠀ , ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀. ⠀ ⠀. ˚ ⠀ ⠀ . . . *⠀ ⠀ ⠀✦answer fast please⠀ . . . ⠀ . ˚ ﾟ . .⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀, * ⠀. . ⠀✦ ˚ * .⠀ .
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1
Answer:
Correct option is
C
3x
2
−19x+3=0
As,
α
2
=5α−3⇒α
2
−5α+3=0
β
2
=5β−3⇒β
2
−5β+3=0
Therefore, α,β are the roots of the equation
x
2
=5x−3
x
2
−5x+3=0
Now,
β
α
+
α
β
=
α.β
α
2
+β
2
=
α.β
(α+β)
2
−2α.β
=
3
25−6
=
3
19
Hence,
The required equation is
x
2
−
3
19
x+1=0
3x
2
−19x+3=0.
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