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a+b+C=0
(a+b+C)² =0
|a|² + |b|² + |c|² +2(a.b +b.c + c.a)=0
As it is given in the question that a, b, C are the unit vectors. Therefore, |a|=|b|=|c|=1.
So,
1+1+1+2(a.b + b.c + c.a)=0
2(a.b + b.c + c.a)= -3
a.b + b.c + c.a = -3/2
Hope it helps.
(a+b+C)² =0
|a|² + |b|² + |c|² +2(a.b +b.c + c.a)=0
As it is given in the question that a, b, C are the unit vectors. Therefore, |a|=|b|=|c|=1.
So,
1+1+1+2(a.b + b.c + c.a)=0
2(a.b + b.c + c.a)= -3
a.b + b.c + c.a = -3/2
Hope it helps.
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