Question

Isitpossibletodesignarectangularmangogrovewhoselengthistwiceitsbreadth,andthe areais800 m2?If so, find its length and breadth.

Answer 1

Let the breadth = x

Now length = 2x

Area = 800 m²

Length× Breadth = 800

2x×x = 800

2x² = 800

x² = 800/2 = 400

x² = 400

x = 20 m

Breadth = 20 m

Length = 40 m

#Be Brainly !!

Answer 2

$\huge \bf \underline{hey}$


$\huge { \mathfrak{here \: is \: answer}}$

let the length be 2x..( since it is twice the breadth )

and breadth = x

given -area=800m2

area of rectangle = length*breadth

length*breadth=800m2

2x*x=800m2

$\sf{2x ^{2} = 800m ^{2} }$

$\sf{ {x}^{2} = \frac{800}{2}}$


$\sf{ {x}^{2} = 400}$


$\sf{x = \sqrt{400} }$


$\bf{x = 20}$

$\bf{length = 2 \times 20 = 40m}$

$\bf{breadth = 20m}$

$\huge \boxed{ \ulcorner{ \mathfrak{hope\: it\: helps}}}$

$\huge { \mathfrak{thanks}}$