Question

..............................

Answer 1

A is the correct option

SOLUTION

holding B constant

[0.4/0.2]^n=2.5*10^-4/2.5*10^-4

2^n=1

2^n=2^0

cancelling base

n=0

rate=k[A]^0

holding A constant

[0.2/0.1]^n=1*10^-3/2.5*10^-4

2^n=4

2^n=2^2

cancelling out base

n=2

rate=k[B]^2

overall rate=k[A]^0[B]^2

hope it helps u......

u will need simple maths to understand this.....