..................."................
Attachments:
Answers
Answered by
2
[0010001111]... Hello User...[1001010101]
Here's your answer...
Let the people who like chess be set A.
Let the people who like cricket be set B.
By logic, those people who like both cricket and chess will be the set AnB.
Also, the people who like chess but no cricket will be set A-B.
The people who like cricket but don't like chess will be B-A.
The people who like either chess or cricket, must be liking either only chess, or only cricket, or both chess and cricket. So these people will be AuB
n(AnB) = 5
n(A-B) = 35
n(B-A) = 15
n(AuB) = n(A-B) + n(B-A) + n(AnB)
= 35+15+5
= 55
55 students like either cricket or chess.
[0010001111]... More questions detected... [010110011110]
//Bot UnknownDude is moving on to more queries
//This is your friendly neighbourhood UnknownDude
Here's your answer...
Let the people who like chess be set A.
Let the people who like cricket be set B.
By logic, those people who like both cricket and chess will be the set AnB.
Also, the people who like chess but no cricket will be set A-B.
The people who like cricket but don't like chess will be B-A.
The people who like either chess or cricket, must be liking either only chess, or only cricket, or both chess and cricket. So these people will be AuB
n(AnB) = 5
n(A-B) = 35
n(B-A) = 15
n(AuB) = n(A-B) + n(B-A) + n(AnB)
= 35+15+5
= 55
55 students like either cricket or chess.
[0010001111]... More questions detected... [010110011110]
//Bot UnknownDude is moving on to more queries
//This is your friendly neighbourhood UnknownDude
Similar questions