Question

Thesumofthe4thand8thtermofanAPis24andthesumofthe6thand10thtermis44.Findthefirstthree
termsofAP.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Given,

T4+T8=24

a+3d+a+7d=24

2a+10d=24....eqn.1

From next part of question,

T6+T10=44.

a+5d+a+9d=44.

2a+14d=44......eqn.2

Fromeqn 1-eqn 2.

2a+10d-(2a+14d)=24-44.

2a+10d-2a-14d=-20.

-4d=-20

So,d=5

Put, d=5 in eqn 1.

2a+10d=24.

2a+10×5=24

2a=24-50

2a=-26

a=-26÷2

a=-13.

Hence, 1st term of A.P=-13.

2nd term of A.P=a+d.

=-13+5=-8.

3rd term of A.P =a+2d.

=-13+2×5.

-13+10=-3.

So,first three term of A.P be-13,-8,-3.