Question

................ .........​

Answer 1

Answer:

Given ABCD is a square with sides 6 cm, circumscribed by a circle.

Radius of the circle = AD/2 = BC/2  (Since AD and BC are the diameters)              -------------------------------------(A)

Now applying Pythagoras theorem in triangle A C D;

AC² + CD² = AD²

Or,

4² + 4² = AD²

Or, AD = 4√2 cm

Now putting the value in (A);

Radius of the circle = 2√2 cm

Now we know that the area of shaded region = Area of circle - Area of square

⇒Pi x r x r - a x a

⇒22/7 x 2√2 x 2√2 - 4 x 4

⇒22/7 x 8 - 16

⇒176/7 - 16

⇒176 - 112/7                                           (After LCM)

⇒9.142 cm² is the area of the shaded region.