Question

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Answer 1

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(SinA * cosA )/(1 + sinA - cosA) + (cosA* sinA)/(1 + cosA - sinA)

= (SinA * cosA) [1/(1 + sinA - cosA) + 1/(1 + cosA -sinA)]

On taking LCM and then solving

= 2 sinA cosA/ 2 sinA cosA

= 1 = RHS .

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Answer 2

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PLEASE REFER THE ATTACHMENT PLEASE....!!

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