Question

a and b are ideal gases the molecular weight of a and b are i the ratio 1:4 .the pressure of a gas mixture containing equal weights of a and b is p atm .what is the partial pressure of b in the mixture

Answer 1

Q. There are two gases A and B whose ratio of mole weight is 4:1. The pressure of the gas containing equal weight of A and B is P. What is the partial pressure of B?

Answer:- This one’s a simple.

Say you’ve “x” weight of each gas in the container. So, from here we calculate the ratio of number of moles of gas in the container.

Since number of moles is weight divided by mass, it is inversely proportional to mass.

Hence, the ratio of number of moles of A to B will be 1:4.

From here we can easily find that partial pressure of A will be .2P and that of B will be .8P

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