Question

ꜱᴏʟᴠᴇ

❌ɴᴏ ꜱᴩᴀᴍᴍɪɴɢ ❌​

Answer 1

Please refer to the attachment.

Answer 2

$\huge\underline\mathcal\blue{Solution}$

Given that the radius of the pipe = 7 cm .

$= \frac{7}{100} m$

Rate of water flowing = 6 km/hr .

• Length of water flowing in 1 hr = 6 km

= 6000 m

• Volume of water flowing through cylindrical pipe in 1 hr

$= \pi {r}^{2} h$

$= \frac{22}{7} \times ({ \frac{7}{100} )}^{2} \times 6000$

$= \frac{22 \times 7 \times 6000}{100 \times 100}$

$= \frac{22 \times 7 \times 6}{10} {m}^{3}$

Level of water raised in 60 m × 22m water tank = 7 cm

$= \frac{7}{100} m$

• Volume of water level of 7 cm height in the tank

$= 60 \times 22 \times \frac{7}{100}$

$= \frac{462}{5}$

$= 92.4 {m}^{3}$

Let in t hrs the level of water rises to 7 cm in tank ,

According to the que ,

Volume of water flowing through pipe in t hr = volume of water level of 7 cm height in the tank

$= > t \times \frac{22 \times 7 \times 6}{10} = 92.4$

$= > t = \frac{92.4 \times 10}{22 \times 7 \times 6}$

$= > t = 1hr$

Hence , the level of water will rise to 7 cm in 1 hr .