Question

×_× °_° ×_× °_° ×_× °_° ×_×


Prove That (sin a + cos a)(tan a + cot a = sec a + cosec a​


°_° ×_× °_° ×_× °_° ×_× °_° ​

Answer 1

Step-by-step explanation:

hope this helps u thank u

Answer 2

$\red{ \small \sf \: (sinA - cosA)(cotA + tanA) = secA - cosecA} \\ \\ \bold{↓ \underline{ LHS} ↓ } \\ \\ (sinA - cosA) \bigg[ \frac{cosA}{sinA}+ \frac{sinA}{cosA} \bigg] \\ \\ \frac{(sinA - cosA)(cos²A + sin²A)}{sinA \: cosA}\\ \\ \frac{(sinA - cosA)(1)}{sinA \: cosA} \\ \\ \frac{(sinA - cosA)}{sinA \: cosA }\\ \\ \frac{1}{cosA }- \frac{1}{sinA} \\ \\ secA - cosecA \\ \\ \bold{↑ RHS ↑ }\\ \\ \: \boxed { \bf \: LHS = RHS } \\ \underline{ \Hence \Proved}$