0 (0,0) A (6,0) B (0,4) are 3 points!
If P Is a point such that area of
Angle POB is twice the area of angle POA,then
the locus of P Is?
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Step-by-step explanation:
The three given points are origin, one on x-axis the other on y-axis . Let P be (x,y). We know that are of triangle
=1/2×base×height
triangle POA = 2 triangle POB
∴1/2×4x=±2×1/2×6×y
or 2x=±6y or x=±3y
Hence the required locus of both the parts is (x−3y)(x+3y)=0
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