Question

(0,0),(1,2),(-1,2) area of a triangle​

Answer 1

Answer:

4 units^2

Step-by-step explanation:

The base of the triangle= 4

Height=2

Area =1/2*b*h

=1/2*4*2

=4

Answer 2

$\huge{\pink{\green{\sf{Area\:of\:triangle=2\:Units}}}}$

Step-by-step explanation:

$\huge{\pink{\green{\underline{\red{\sf{SOLUTION-}}}}}}$

$Let \: \triangle be \: ABC \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: { \orange{ \underline{given}}} \\ { \green{coordinate \: of \: A = (0,0)}} \\ { \green{coordinate \: of \: B= (1,2)}} \\{ \green{coordinate \: of \: C= ( - 1,2)}} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: { \red{ \underline{to \: find :}}} \\ { \purple{area \: of \: triangle \: Abc =? }}$

▪According to given question:

▪We know all the three coordinates of triangle. So,we know the formula to find area of triangle by their given coordinate.

$\to Area \: of \: triangle = \frac{1}{2}( x_{1} ( y_{2} - y_{3}) + x_{2}( y_{3} - x_{1}) + x_{3}( y_{1} - y_{2}))$

$\to Area=\frac{1}{2}(0(2-2)+1(2-0)+(-1)(0-2)\\\to Area=\frac{1}{2}(0+2+2)\\\to Area=\frac{1}{2}(4)\\{\green{\to Area=2\:units}}$

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