0/0=2 is possible then prove it?
innervoice:
jii btayein
Answers
Answered by
2
HERE YOU GO...
LET THE VALUE OF
X=Y=1
AT L.H.S =(X^2-Y^2) / (X-Y)
( X+Y) (X-Y) / (X-Y)
NOW CANCEL (X-Y) FROM BOTH NUMERATOR AND DENOMINATOR
YOU WILL GET IN (X+Y ) IN NUMERATOR. ...I.e 2
AT RHS
AT NUMERATOR (X^2+Y^2 - 2XY)
AND DENOMINATOR (X-Y)
PUTTING THE VALUE OF X AND Y I.e 1
YOU WILL GET 0/0
HRNCE 0/0=2
PROVED
LET THE VALUE OF
X=Y=1
AT L.H.S =(X^2-Y^2) / (X-Y)
( X+Y) (X-Y) / (X-Y)
NOW CANCEL (X-Y) FROM BOTH NUMERATOR AND DENOMINATOR
YOU WILL GET IN (X+Y ) IN NUMERATOR. ...I.e 2
AT RHS
AT NUMERATOR (X^2+Y^2 - 2XY)
AND DENOMINATOR (X-Y)
PUTTING THE VALUE OF X AND Y I.e 1
YOU WILL GET 0/0
HRNCE 0/0=2
PROVED
Answered by
1
hey mate...
here is your answer
hope it helps
here is your answer
hope it helps
Attachments:

Similar questions