Question

0 0
33. If the line 2x - 3y - 5 = 0 is the
perpendicular bisection of the line segment
joining (3, - 4) and (a, b) find a +B
Sol: If(a, b) is the reflection of (3,-4) in the line
2x – 3y - 5 = 0 , then
a-3 B+4 -2(6+12-5).
2x-3y-5=0
2 -3 (2)²+(-3)²
(ap) :
a-3 B+4
=-2 => a=-1, B= 2
2 -3
..a+B=-1+
2 a +B=1​

Answer 1

Answer:

In △ABC AB=AC

⇒∠B=∠C (Angles opposite to equal sides are equal)

Now using angle sum property

∠A+∠B+∠C=180

∘

⇒80

∘

+∠C+∠C=180

∘

⇒2∠C=180

∘

−80

∘

⇒∠C=

2

100

∘

=50

∘

now ∠C+∠x=180

∘

(Angles made on straight line (AC) are supplementary)

⇒50

∘

+∠x=180

∘

⇒∠x=180

∘

−50

∘

=130

∘

@ARSH

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