Question

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FBMS 1:1
(Q:42) Number of observations N=10. Mean X=
22, Mean Y=15, Sum of squared deviations of X
from mean value = 120, Sum of squared deviation
of Y from mean value=144. Sum of multiplication
of deviation of X and Y =124.From the above
details the coefficient of correlation will be​

Answer 1

Answer:

Given

Sum of squared deviation of X= 148

Sum of squared deviation of Y...

Answer 2

Given :  Number of observations N=10. Mean X=  22, Mean Y=15, Sum of squared deviations of X  from mean value = 120, Sum of squared deviation  of Y from mean value=144. Sum of multiplication  of deviation of X and Y =124.

To Find : the coefficient of correlation

Solution:

Number of observations N=10

Mean X=   22,

Sum of squared deviations of X  from mean value = 120,

Variance X =  120/10   = 12

std deviation (X) = √12

Mean Y=   15,

Sum of squared deviations of Y from mean value = 144,

Variance Y =  144/10   = 14

std deviation (Y) = √14

Sum of multiplication  of deviation of X and Y =124.

cov (x,y) =   124/10  = 12.4

Correlation coefficient = cov (x,y)/ (std deviation (x) ×std deviation (y))

= 12.4  / (√12 * √14)

= 0.957

coefficient of correlation = 0.957

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