Question

0+0+∆= 68•06 kg
0+∆+∆+∆= 19180 gm
0+∆=?
Find what is the value of 0+∆

Answer 1

let oval be x
triangle be y
so according to the question
2x+ y= 68.06 kg (1)
19180gm= 19.18kg
thus x+ 3y= 19.18 (2)

using (1)&(2)
y= 68.06-2x
x+ 3(68.06-2x)= 19.18
x + 204.18 -6x = 19.18
204.18 - 19.18 = 5x
185= 5x
$x = 37$
y= 68.06-2x
y= 68.06- 74
$y = - 5.94$
thus x+y
= 37-5.94
= 31.06kg