(∩ ͡° ͜ʖ ͡°)⊃━炎炎炎炎炎炎炎炎
Question for maths expert......
Attachments:

Answers
Answered by
1
a10= alpha^10 - beta^10
a8= alpha^8 - beta^8
a9= alpha^9 - beta^9
a10 -2a8/2a9= alpha^10 - beta^10 - 2alpha^8 + 2beta^8/ 2 ( alpha^9 - beta^9)
= alpha^8( alpha^2 -2) - beta^8( beta^2 - 2)/
2( alpha^9 - beta^9)
As alpha and beta are roots ofx^2 - 6x -2= 0
alpha^2 - 6 alpha -2= 0
alpha^2 -2 = 6 alpha
beta^2 - 6 beta -2 = 0
beta^2 -2= 6 beta
put in alpha^8( alpha^2 -2) - beta^8( beta^2 -2)/ 2( alpha^9- beta^9)
= alpha^8 × 6 alpha - beta^8( 6 beta)/ 2( alpha^9 - beta^9)
= 6( alpha^9 - beta^9)/ 2( alpha^9- beta^9)
=3
✌✌✌Dr.Dhruv✌✌✌✌✌
✌✌✌✌✌Senior Chairman of Resdtind ✌✌✌✌✌
a8= alpha^8 - beta^8
a9= alpha^9 - beta^9
a10 -2a8/2a9= alpha^10 - beta^10 - 2alpha^8 + 2beta^8/ 2 ( alpha^9 - beta^9)
= alpha^8( alpha^2 -2) - beta^8( beta^2 - 2)/
2( alpha^9 - beta^9)
As alpha and beta are roots ofx^2 - 6x -2= 0
alpha^2 - 6 alpha -2= 0
alpha^2 -2 = 6 alpha
beta^2 - 6 beta -2 = 0
beta^2 -2= 6 beta
put in alpha^8( alpha^2 -2) - beta^8( beta^2 -2)/ 2( alpha^9- beta^9)
= alpha^8 × 6 alpha - beta^8( 6 beta)/ 2( alpha^9 - beta^9)
= 6( alpha^9 - beta^9)/ 2( alpha^9- beta^9)
=3
✌✌✌Dr.Dhruv✌✌✌✌✌
✌✌✌✌✌Senior Chairman of Resdtind ✌✌✌✌✌
Anonymous:
Awesome✊
Similar questions
Math,
9 months ago
Math,
9 months ago
Physics,
1 year ago
Social Sciences,
1 year ago
English,
1 year ago