Question

0.001 M solution of sodium chloride NACL contain ______ grams of sodium chloride

Answer 1

Answer:

0.0001 sodium chloride

Answer 2

Given:

Concentration of given sodium chloride solution= 0.001M

To find:

Weight of sodium chloride

Solution:

First, define molarity- It is define as number of moles required in 1 liters of solution.

To calculate the weight formula, used is -

     $M = \frac{n}{V}$

Here, M = molarity( moles L⁻¹)

         n = number of moles (moles)

        V = volume of solution ( 1 L)

because volume of solution is 1L. So, no. of moles is equal to the molarity

i.e. n = 0.001 moles

now, to find given weight, formula is

   $n = \frac{w}{molar mass}$

therefore, w = n × molar mass

here, w = given weight

         molar mass of NaCl = 58.5 gmol⁻¹

so,

   w = 0.001 × 58.5

  w = 0.059g

Therefore, 0.059g of NaCl is required to make 0.001M solution of sodium chloride.