Question

0.001Mof HCl is provided find [OH-]ion​

Answer 1

Answer:

Ca ( OH)2 》 Ca+2 + 2 OH-

0.001M of Ca(OH)2 gives 0.002 M of OH- ions

so H+ ions concentration = Kw / [ OH-]

= 1 × 10^-14 / 2 × 10^-3

= 5 x 10^-12

pH = -log [H+]= 11.301

Answer 2

Answer:

Explanation:

0.11

Is the answer