Question

0.01 M Solution of a monobasic acid
dissociates to the extent of 10%
calculate the dissociation constant
of the acid.​

Answer 1

Explanation:

Dissociation constant is K

a

=10

−3

pK

a

=−logK

a

=−log[10

−3

]=+3

From hinderson's equation,

pH=pK

a

+log

[Acid]

[Salt]

⇒pH=3+log

0.1

1

=3−1=2

pH=2