Question

0.01 M solution of h2a has ph equals to 4. if ka for the acid is 4.45*10^-7,the concentration of ha^- ion in solution would be

Answer 1

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Answer 2

We know that Ka1>ka2 so we neglect ka2

Ka1=(Ha^-) (H+)

Ha^- = Ka1/H+

pH = - log(H+)

= 10^-4

(Ha^-) = 4.45 ×10^-5