Question

0.01 mole of sodium hydroxide is added to 10 litres of water. how will the pH of water change​

Answer 1

Answer:

0.01 mole of sodium hydroxide is added to 10 litres of water. How will the pH of water change?

When will Lunchclub be active in New Delhi?

Lunchclub is now virtual and finally open to users in New Delhi! Network from home and make relevant connections locally and glob

The weight of 0.01 mole of NaOH = Strength * molecular weight

= 0.01 * 40

= 0.4 grams

Weight of NaOH in 10 litres of water = 0.4/10 = 0.04 grams

Concentration = 0.04/40 = 0.001

pOH = log(concentration of NaOH)

= log (0.001)

=3

pH =14-Poh

= 14-3

=11

So ph of water will change from 7 to 11 by adding 0.01 mole of NaOH in 10 liters of water.

Answer 2

The pH of water changes from 7 to 11.

Given:

0.01 mole of sodium hydroxide is added to 10 litres of water.

To Find:

How will the pH of water change​

Solution:

We can simply solve this problem by using the following process.

$[OH^{-} ]$ = Number of moles ÷ Quantity of water

$[OH^{-} ]=\frac{0.01}{10}$

1 × $10^{-3}$

Now,

pOH = $-log[OH^{-} ]$

pOH = 3

Therefore,

pH = 14 - pOH

pH = 14 - 3

pH = 11

Hence, the pH of water changes from 7 to 11 by 4.

#SPJ3