0.01 moles of iodoform reacts with silver to form a gas whose volume at stp is
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Hey there,
The formula is 2CHI3 + 6AG = 2C2H2+6AGI2 which is equal to 22400ml where Ag is Silver and CHI3 is iodoform.
We are given 0.01moles which is equivalent to 112ml
Since 2 moles of iodoform reacts to form 22400 ml at NTP therefore 0.01 moles of iodoform reacts to form 112 ml at NTP, and this can be calculated by (22400/2) X 0.01.
Thanks for asking.
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