Question

0.01 of moles of koh solution present in 100ml of solution and what is n of koh (here n =no. of moles)​

Answer 1

Answer:

Explanation:

Molarity=   GMW of KOH

Weight of KOH

​

×  

Vol(ml)

1000

​

             

[GMW of KOH= Atomic weight of K+ atomic weight of O+ atomic weight of H=10+16+1=27]

⇒0.1=  

27

Weight of KOH

​

×  

100

1000

​

                         

Weight of KOH=  

10

2.7

​

 

Weight of KOH=0.27 g