Question

0.01 solution of NaCl offered a resistance of 200 Ohm in a conductivity cell at 298 Kelvin if the cell constant of the cell is unity calculate molar conductivity of the solution.​

Answer 1

Answer:

κ =

R

cellconstant

κ = 200^1

∧ m =κ M1000

∧ m = 0.01∗200^1000

^ m = 500 Scm 2 mol −1

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