0. 02 m ammonia solution is 5% ionized, so its ph is: (1) 2 (2) 11 (3) 50 (4) 7
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Answer:
2 option is correct
Explanation:
[ H+ ] = C× ionisation constant
0.02 ×5÷100
1%1000
pOH =3
pH= 14- 3=11
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