Question

0.020 mol of glucose is dissolved in 200ml of water at 300k calculate the osmotic pressure of the solution​

Answer 1

Answer:

this is chemistry

sorry I didn't no

Answer 2

Osmotic pressure of the solution is $P= 2.463 atmosphere$

Explanation:

According to the Ideal gas equation we have $PV=nRT$

Then pressure will be equal to

$P= nRT/V$

Given  

• number of moles of glucose =$0.020 mol$
• The Volume of water in which glucose is dissolved =$200ml$

        Temperature= $300k$    R rate constant =$0.0821L.atm mol 'K$

• Substituting the value of number of moles, temperature and volume in  ideal gas equation
• P = $0.020$×$0.0821$×$300/0.2$

• Pressure =$P= 2.463 atmosphere$
• Osmotic pressure of the solution is  $P= 2.463 atmosphere$

• Osmotic pressure of the solution is the minimum pressure which is required to stop the inflow of the solvent.